Answer
$(3x-5y),(9x^2+25y^2+15xy)$
Work Step by Step
Given: $27x^3-125y^3$
This implies that
$=(3x)^3-(5y)^3$
or, $=(3x-5y)[(3x)^2+(5y)^2+(3x)(5y)]$
Hence, our Factors are: $(3x-5y),(9x^2+25y^2+15xy)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 84
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