Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 21

Answer

$15x^2y^2+2xy-8$

Work Step by Step

Given:$P(x)=(3xy-2)(5xy+4)$ Multiply the given polynomials. This implies $=3xy(5xy+4)-2(5xy+4)$ or, $=15x^2y^2+12xy-10xy-8$ Hence, the result is : $P(x)=15x^2y^2+2xy-8$
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