Answer
Three Factors are :$-2y^2(y-3)(y-9)$
Work Step by Step
Given:$-2y^4+24y^3-54y^2$
Take the common terms out.
Thus,
$=-2y^2(y^2-12y+27)$
or, $=-2y^2(y^2-9y-3y+27)$
or, $=-2y^2(y-3)(y-9)$
Hence, Three Factors are :$-2y^2(y-3)(y-9)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 70
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