Answer
$(x-3),(x+3),(x^2+9)$
Work Step by Step
Given: $x^4-81$
This implies that
$=(x^2)^2-(9)^2$
or, $=(x^2-9)(x^2+9)$
or, $=(x-3)(x+3)(x^2+9)$
Hence, our Factors are: $(x-3),(x+3),(x^2+9)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 82
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