Answer
$4,(a+2),(a^2+4-2a)$
Work Step by Step
Given: $4a^3+32$
This implies that
$=4(a^3+8)$
or, $=4(a^3+2^3)$
or, $=4(a+2)(a^2+4-2a)$
Hence, our Factors are: $4,(a+2),(a^2+4-2a)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 81
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