Answer
$(x^2-3)^2$ or, $(x^2-3)(x^2-3)$
Work Step by Step
Given: $x^4-6x^2+9$
or, $=(x^2)^2-6x^2+9$
This implies
$=(x^2)^2-3x^2-3x^2+9$
or, $=(x^2-3)(x^2-3)$
Hence, Factors are: $(x^2-3)^2$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 79
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