Answer
$21$
Work Step by Step
Given:$f(x) \cdot g(x)=(x-3)(2x+5)$
or,$=x(2x+5)-3(2x+5)$
or, $=2x^2+5x-6x-15$
Thus, $f(x) \cdot g(x)=2x^2-x-15$
Plug $x=-4$ in above equation, we have
$f(-4) \cdot g(-4)=2(-4)^2-(-4)-15=36-15=21$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 28
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