Answer
$(x+3-2a),(x+3+2a)$
Work Step by Step
Given: $x^2+6x+9-4a^2$
or, $=x^2+3x+3x+9-4a^2$
This implies
$=(x+3)(x+3)-(2a)^2$
or, $=(x+3)^2-(2a)^2$
Hence, Factors are: $(x+3-2a),(x+3+2a)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 76
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