Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 46b

Answer

$x=\dfrac{11}{3}$

Work Step by Step

Expressing the terms on both sides of the equal sign in the same base so that the exponents can be equated results to \begin{array}{l} 125^{x-3}=25 \\\\ (5^3)^{x-3}=5^2 \\\\ 5^{3x-9}=5^2 \\\\ 3x-9=2 \\\\ 3x=11 \\\\ x=\dfrac{11}{3} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.