Answer
$\dfrac{1}{2x+1}$
Work Step by Step
The expression $
\dfrac{2-\dfrac{1}{x}}{4x-\dfrac{1}{x}}
$ simplifies to
\begin{array}{l}
\dfrac{\dfrac{2x-1}{x}}{\dfrac{4x^2-1}{x}}
\\\\=
\dfrac{2x-1}{4x^2-1}
\\\\=
\dfrac{2x-1}{(2x-1)(2x+1)}
\\\\=
\dfrac{1}{2x+1}
.\end{array}
