Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 29a

Answer

$\dfrac{5\sqrt{5}}{12}$

Work Step by Step

Using the properties of radicals, the expression $ \dfrac{\sqrt{45}}{4}-\dfrac{\sqrt{5}}{3} $ simplifies to \begin{array}{l} \dfrac{\sqrt{9\cdot5}}{4}-\dfrac{\sqrt{5}}{3} \\\\= \dfrac{3\sqrt{5}}{4}-\dfrac{\sqrt{5}}{3} \\\\= \dfrac{3(3\sqrt{5})-4(\sqrt{5})}{12} \\\\= \dfrac{9\sqrt{5}-4\sqrt{5}}{12} \\\\= \dfrac{5\sqrt{5}}{12} .\end{array}
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