Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 27b

Answer

$\dfrac{5\sqrt{x}}{2}$

Work Step by Step

Using the properties of radicals, the expression $ \dfrac{\sqrt{50x}}{2\sqrt{2}} $ simplifies to \begin{array}{l} \dfrac{1}{2}\sqrt{\dfrac{50x}{2}} \\\\= \dfrac{1}{2}\sqrt{25x} \\\\= \dfrac{1}{2}\cdot5\sqrt{x} \\\\= \dfrac{5\sqrt{x}}{2} .\end{array}
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