Answer
$1$
Work Step by Step
Using $i^2=-1$, the expression $
i^{-12}
$ is equivalent to
\begin{array}{l}
\dfrac{1}{i^{12}}
\\\\=
\dfrac{1}{(i^2)^6}
\\\\=
\dfrac{1}{(-1)^6}
\\\\=
\dfrac{1}{1}
\\\\=
1
\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 10 - Cumulative Review - Page 634: 35d
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