Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 46a

Answer

$x=\dfrac{1}{3}$

Work Step by Step

Expressing the terms on both sides of the equal sign in the same base to equate the exponents results to \begin{array}{l} 64^x=4 \\\\ (4^3)^x=4 \\\\ 4^{3x}=4^1 \\\\ 3x=1 \\\\ x=\dfrac{1}{3} .\end{array}
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