Answer
$2x-5$
Work Step by Step
Factor $2x^2-x-10$ to obtain $(2x-5)(x+2)$.
Thus,
$\require{cancel}
(2x^2-x-10) \div (x+2)
\\=[(2x-5)(x+2)] \div (x+2)
\\=\dfrac{(2x-5)(x+2)}{x+2}
\\=\dfrac{(2x-5)\cancel{(x+2)}}{\cancel{x+2}}
\\=2x-5$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 10 - Cumulative Review - Page 634: 15
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