Answer
$(g\circ f)(x)=-3x^2+9x-1$
Work Step by Step
Since $
(g\circ f)(x)=g(f(x))
$, then,
\begin{array}{l}
(g\circ f)(x)=g(x^2-3x+2)
\\\\
(g\circ f)(x)=-3(x^2-3x+2)+5
\\\\
(g\circ f)(x)=-3x^2+9x-6+5
\\\\
(g\circ f)(x)=-3x^2+9x-1
\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 10 - Cumulative Review - Page 634: 42c
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