Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 24d

Answer

$-7$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the expression $ \left( 3\sqrt{2}+5 \right)\left( 3\sqrt{2}-5 \right) $ is equivalent to \begin{array}{l} \left( 3\sqrt{2} \right)^2-(5)^2 \\\\= 9\cdot2-25 \\\\= 18-25 \\\\= -7 .\end{array}
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