Answer
$\lambda = 1.23\times 10^{-9}~m$
Work Step by Step
We can use Equation (38-20) to find the wavelength:
$K = \frac{h^2}{2m \lambda^2}$
$\lambda^2 = \frac{h^2}{2m~K}$
$\lambda = \sqrt{\frac{h^2}{2m~K}}$
$\lambda = \sqrt{\frac{(6.63\times 10^{-34}~J~s)^2}{(2)(9.109\times 10^{-31}~kg)~(1.00~eV)(1.6\times 10^{-19}~J/eV)}}$
$\lambda = 1.23\times 10^{-9}~m$
