Chapter 38 - Photons and Matter Waves - Problems - Page 1183: 41d

$\Delta \lambda = 2.43\times 10^{-12}~m$

We can find the Compton shift $\Delta \lambda$: $\Delta \lambda = \frac{h}{mc}(1-cos~\phi)$ $\Delta \lambda = \frac{h}{mc}(1-cos~90^{\circ})$ $\Delta \lambda = \frac{h}{mc}$ $\Delta \lambda = \frac{6.63\times 10^{-34}~J~s}{(9.109\times 10^{-31}~kg)(3.0\times 10^8~m/s)}$ $\Delta \lambda = 2.43\times 10^{-12}~m$