Answer
$\frac{R}{\lambda}=201$
Work Step by Step
In the previous section of this problem, we have calculated
$λ=2.486\times 10^{-8}$ $nm$
or, $λ=0.02486$ $fm$
If the target nucleus has radius $R=5.0$ $fm$, the ratio $\frac{R}{\lambda}$ is given by
$\frac{R}{\lambda}=\frac{5.0}{0.02486}\approx 201$
