Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 475: 51

Answer

$\ln(\sqrt{x}\cdot y)$

Work Step by Step

$\displaystyle \frac{1}{2}\ln x+\ln y=\quad $...apply the Power Rule: $\quad \log_{b}(M^{p})=p\cdot\log_{b}\mathrm{M}$ $=\ln x^{1/2}+\ln y\quad $...apply the Power Rule: $\quad \log_{b}(M^{p})=p\cdot\log_{b}\mathrm{M}$ $=\ln(x^{1/2}y)$
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