Answer
$\log{\frac{3x+7}{x}}$
Work Step by Step
RECALL:
(i) $\log_b{M} - \log_b{N} = \log_b{\frac{M}{N}}.$
(ii) $\log_b{b^x}=x.$
Use rule (i) above with $M=3x+7$ and $N=x$ to obtain
$\log{\frac{3x+7}{x}}.$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 475: 48
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