Answer
$\log_8{13} + \log_8{7}$
Work Step by Step
RECALL:
$\log_b{MN}=\log_b{M} + \log_b{N}$ (Product Rule).
Use the product rule with $M=13$ and $N=7$ to obtain
$\log_8{13} + \log_8{7}.$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 475: 2
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