Answer
$7 \cdot \log_b{x}$
Work Step by Step
RECALL:
(1) $\log_b{\frac{M}{N}}=\log_b{M}-\log_b{N}$
(2) $\log_b{(b^x)}=x$
(3) $\log_b{(a^n)} = n \cdot \log_b{a}$
Use rule (3) above with $n=7$ to obtain
$=7 \cdot \log_b{x}$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 475: 16
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