Answer
$5$
Work Step by Step
RECALL:
(i) $\log_b{M} - \log_b{N} = \log_b{\frac{M}{N}}.$
(ii) $\log_b{b^x}=x.$
Use rule (i) above with $M=96$ and $N=3$ to obtain
$\log_2{\frac{96}{3}}
\\=\log_2{32}
\\=\log_2{2^5}.$
Use rule (ii) above to obtain
$5.$
