Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.1 - Inverse Functions and Their Derivatives - Exercises 7.1 - Page 373: 49

Answer

Proof given below.

Work Step by Step

Select any two different values, $x_{1}$ and $x_{2}$ from the domain of f. If $x_{1}\neq x_{2}$, one must be greater than the other. Without loss of generality, say that we chose $x_{1}$ to be the smaller number. So, we have $x_{1}\lt x_{2}$. If the function is increasing, then $\quad f(x_{1})\lt f(x_{2}).$ If the function is decreasing, then $\quad f(x_{1})\gt f(x_{2}).$ In either case, the inequality is strict, meaning that $f(x_{1})\neq f(x_{2})$ Therefore, $ x_{1}\neq x_{2}\Rightarrow f(x_{1})\neq f(x_{2})$ QED.
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