Answer
$$ f^{-1}(x)=\sqrt[3]{x+1}$$
Work Step by Step
Given $$ y=x^{3}-1$$
Find the inverse:
\begin{aligned}
& y=x^{3}-1\\
& \Rightarrow x^{3}=y+1 \\
&\Rightarrow x=\sqrt[3]{ y+1}, \\\cr
& \text{Switch $ x $ and $ y $:} \\
&y=\sqrt[3]{x+1}=f^{-1}(x)
\end{aligned}