Answer
$$\frac{13}{12}$$
$$Or$$
$$1.083$$
Work Step by Step
$$\int_{0}^{1}(x^3(2x^4+1)^2)dx$$
$u=2x^4$
$du=8x^3dx$
$\frac{1}{8}du=x^3dx$
$$\frac{1}{8} \int_{0}^{1}u^2du$$
$\frac{1}{8} *_{0}^{1} |\frac{1}{3} u^3$
$\frac{1}{24}*_{0}^{1}|(2x^4+1)^3$
$$\frac{1}{24}(3^3-1)=\frac{26}{24}=\frac{13}{12}=1.083$$
