Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.5 Exercises - Page 302: 48

Answer

$\frac{2}{45}(3x-4)^{\frac{5}{2}}+\frac{8}{27}(3x-4)^{\frac{3}{2}}+C$

Work Step by Step

Find the indefinite integral using the same method from Example 5 Let $u=3x-4$, $,x=\frac{u+4}{3}$, and $du=3dx$ $\int x\sqrt {3x-4}dx$ $\frac{1}{3}\int \frac{u+4}{3}u^{\frac{1}{2}}du$, substitute $\frac{1}{9} \int (u^{\frac{3}{2}} +4u^{\frac{1}{2}})du$, Integrate $\frac{1}{9}(\frac{2}{5}u^{\frac{5}{2}} +\frac{8}{3}u^{\frac{3}{2}})+C$ $\frac{2}{45}(3x-4)^{\frac{5}{2}}+\frac{8}{27}(3x-4)^{\frac{3}{2}}+C$
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