Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 84

Answer

{$-4,-2$}

Work Step by Step

Simplify. $ (x^2+6x)^{\frac{1}{3}}=-2$ Take cubic on both sides. we have, $ (x^2+6x)=(-2)^3$ or, $x^2+6x+8=0$ After factorziation,we have Thus, $(x+2)(x+4)=0$ Hence, we can conclude that $x=${$-4,-2$}
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