Answer
$2x^2\sqrt{6x}$
Work Step by Step
Simplify. $\sqrt{6x^3}\sqrt{4x^2}$
As per definition of square root property,we have $(p)^{\frac{m}{n}}=(\sqrt[n] {p})^m$
Thus, the given radical term can be written as:
$\sqrt{6x^3}\sqrt{4x^2}=\sqrt{(6x^3)(4x^2)}$
Since, the power raised to a same exponent or base gets add when they are in multiply form.
or,$=\sqrt{24x^{3+2}}$
or, $=\sqrt{24x^{5}}$
or, $=\sqrt{4x^{4}}\sqrt{6x}$
or,$=\sqrt{(2x^2)^2}\sqrt{6x}$
Hence, the above exponent in radical form can be written as: $2x^2\sqrt{6x}$
