Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 79

Answer

$\dfrac{2}{5-\sqrt{21}}$

Work Step by Step

Simplify. $ \dfrac{\sqrt 7+ \sqrt 3}{\sqrt 7 -\sqrt 3}$ Now, $ \dfrac{\sqrt 7+ \sqrt 3}{\sqrt 7 -\sqrt 3}= \dfrac{\sqrt 7+ \sqrt 3}{\sqrt 7 -\sqrt 3} \times \dfrac{\sqrt 7- \sqrt 3}{\sqrt 7 -\sqrt 3}$ or, $=\dfrac{(\sqrt 7)^2-(\sqrt 3)^2}{7+3-2\sqrt 7 \sqrt 3}$ $\implies \dfrac{2}{5-\sqrt{21}}$
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