Answer
$(3x+y^2)\sqrt[3]{x}$.
Work Step by Step
The given expression is
$=\sqrt[3]{27x^4}+\sqrt[3]{xy^6}$
Factor radicands as a perfect cube.
$=\sqrt[3]{3^3x^3x}+\sqrt[3]{x(y^2)^3}$
Simplify.
$=3x\sqrt[3]{x}+y^2\sqrt[3]{x}$
Use the distributive property.
$=(3x+y^2)\sqrt[3]{x}$.
