Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 49

Answer

$\frac{x\sqrt{x}}{10y^2}$.

Work Step by Step

$=\sqrt{\frac{x^3}{100y^4}}$ Use quotient rule. $=\frac{\sqrt{x^3}}{\sqrt{100y^4}}$ $=\frac{\sqrt{x^2\cdot x}}{\sqrt{10^2y^4}}$ Use product rule. $=\frac{\sqrt{x^2}\sqrt{x}}{\sqrt{10^2y^4}}$ Simplify. $=\frac{x\sqrt{x}}{10y^2}$.
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