Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 48

Answer

$\frac{2}{5}\sqrt[3] {2}$.

Work Step by Step

$=\sqrt[3] {\frac{16}{125}}$ Use quotient rule. $=\frac{\sqrt[3] {16}}{\sqrt[3] {125}}$ Factor each term as a perfect cube. $=\frac{\sqrt[3] {2^3\cdot 2}}{\sqrt[3] {5^3}}$ Use product rule. $=\frac{\sqrt[3] {2^3}\cdot \sqrt[3] {2}}{\sqrt[3] {5^3}}$ Simplify. $=\frac{2\sqrt[3] {2}}{5}$ $=\frac{2}{5}\sqrt[3] {2}$.
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