Answer
$2x\sqrt {5x}$
Work Step by Step
Simplify . $\sqrt{20x^3}$
As per the product rule, we have $\sqrt[n] {pq}=\sqrt[n] {p}\sqrt[n] {q}$
$\sqrt{20x^3}=\sqrt {20}\sqrt {x^3}$
Thus,
$=\sqrt {4 \cdot 5} \sqrt{(x)^3}$
or, $=\sqrt {4x^2} \sqrt {5x}$
Hence, the above exponent in radical form can be written as: or, $2x\sqrt {5x}$
