Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 54

Answer

$10x^2\sqrt{xy}$.

Work Step by Step

$=\frac{\sqrt{200x^3y^2}}{\sqrt{2x^{-2}y}}$ Use quotient rule. $=\sqrt{\frac{200x^3y^2}{2x^{-2}y}}$ Simplify. $=\sqrt{100x^{3+2}y^{2-1}}$ $=\sqrt{100x^{5}y^{1}}$ Factor as a perfect square. $=\sqrt{10^2x^{4}xy}$ Use product rule. $=\sqrt{10^2x^{4}}\sqrt{xy}$ Simplify. $=10x^2\sqrt{xy}$.
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