Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 42

Answer

$xyz^2\sqrt[5] {(16y^4z)}$.

Work Step by Step

The given expression is $=\sqrt[5] {2x^4y^3z^4}\cdot \sqrt[5] {8xy^6z^7}$ Use the product rule. $=\sqrt[5] {2x^4y^3z^4\cdot 8xy^6z^7}$ Simplify. $=\sqrt[5] {16x^5y^9z^{11}}$ Factor the terms. $=\sqrt[5] {16x^5y^5y^4z^{10}z}$ Group the powers of $5$. $=\sqrt[5] {(x^5y^5z^{10})(16y^4z)}$ Use the product rule $=\sqrt[5] {(x^5y^5z^{10})}\sqrt[5] {(16y^4z)}$ Simplify. $=xyz^2\sqrt[5] {(16y^4z)}$.
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