Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 577: 55

Answer

$6 \sqrt{2}+12\sqrt{5}$.

Work Step by Step

The given expression is $=\sqrt3(2\sqrt6+4\sqrt{15})$ Use the distributive property. $=\sqrt3(2\sqrt6)+\sqrt3(4\sqrt{15})$ Use product rule. $=2\sqrt{6\cdot 3}+4\sqrt{15\cdot3}$ Simplify. $=2\sqrt{18}+4\sqrt{45}$ Factor as a perfect square. $=2\sqrt{3^2\cdot 2}+4\sqrt{3^2\cdot 5}$ Use product rule. $=2\sqrt{3^2}\cdot \sqrt{2}+4\sqrt{3^2}\cdot \sqrt{5}$ Simplify. $=2\cdot 3 \sqrt{2}+4\cdot 3\sqrt{5}$ Multiply. $=6 \sqrt{2}+12\sqrt{5}$.
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