Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Review Exercises: Chapter 12 - Page 843: 52

Answer

3.

Work Step by Step

${{5}^{x}}=125$ Simplify the exponent ${{5}^{x}}=125$ as follows. $\begin{align} & {{5}^{x}}=125 \\ & {{5}^{x}}={{5}^{3}} \\ \end{align}$ Use the principle of exponent equality and solve. $x=3$ Check: Substitute $x=3$ in the given equation. $\begin{matrix} {{5}^{3}}\overset{?}{\mathop{=}}\,125 \\ 125=125 \\ \end{matrix}$ Thus, the obtained solution is correct.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.