Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Review Exercises: Chapter 12 - Page 843: 24

Answer

The equivalent logarithmic equation for the exponential equation is: ${{2}^{-3}}=\frac{1}{8}$ is $-3={{\log }_{2}}\frac{1}{8}$.

Work Step by Step

${{2}^{-3}}=\frac{1}{8}$ The function ${{2}^{-3}}=\frac{1}{8}$ is in the form ${{a}^{m}}=x$. Here, $m=-3,a=2\text{ and }x=\frac{1}{8}$ Thus, the equivalent logarithmic equation is ${{\log }_{a}}x=m$. This gives: $-3={{\log }_{2}}\frac{1}{8}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.