Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Review Exercises: Chapter 12 - Page 843: 15

Answer

${{g}^{-1}}\left( x \right)=\frac{2x-1}{3}$.

Work Step by Step

$g\left( x \right)=\frac{3x+1}{2}$ Evaluate the inverse of the function $g\left( x \right)=\frac{3x+1}{2}$ as follows. Replace the function $f\left( x \right)$ with $y$. $y=\frac{3x+1}{2}$ Interchange the variables x and y. $x=\frac{3y+1}{2}$ Solve for the value of y. $\begin{align} & x=\frac{3y+1}{2} \\ & 2x=3y+1 \\ & 3y=2x-1 \\ & y=\frac{2x-1}{3} \end{align}$ Replace y with ${{g}^{-1}}\left( x \right)$ as follows. ${{g}^{-1}}\left( x \right)=\frac{2x-1}{3}$
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