Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Review Exercises: Chapter 12 - Page 843: 16

Answer

${{f}^{-1}}\left( x \right)=\frac{\sqrt[3]{x}}{3}$.

Work Step by Step

$f\left( x \right)=27{{x}^{3}}$ Evaluate the inverse of the function $f\left( x \right)=27{{x}^{3}}$ as follows. Replace the function $f\left( x \right)$ with y. $y=27{{x}^{3}}$ Interchange the variables x and y. $x=27{{y}^{3}}$ Solve for the value of y. $\begin{align} & x=27{{y}^{3}} \\ & {{y}^{3}}=\frac{x}{27} \\ & y=\sqrt[3]{\frac{x}{27}} \\ & y=\frac{\sqrt[3]{x}}{3} \end{align}$ Replace y with ${{f}^{-1}}\left( x \right)$ as follows. ${{f}^{-1}}\left( x \right)=\frac{\sqrt[3]{x}}{3}$
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