Answer
The equivalent expression for ${{\log }_{a}}5+{{\log }_{a}}8$ is ${{\log }_{a}}40$.
Work Step by Step
${{\log }_{a}}5+{{\log }_{a}}8$.
Apply the product rule for logarithms.
$\begin{align}
& {{\log }_{a}}5+{{\log }_{a}}8={{\log }_{a}}\left( 5\cdot 8 \right) \\
& ={{\log }_{a}}40
\end{align}$
