Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Review Exercises: Chapter 12 - Page 843: 23

Answer

$\frac{1}{2}$.

Work Step by Step

${{\log }_{16}}4$ The value of the expression ${{\log }_{16}}4$ is calculated as follows. Assume ${{\log }_{16}}4=x$. ${{\log }_{16}}4$ means ${{16}^{x}}=4$ The value of x is calculated as follows. $\begin{align} & {{16}^{x}}=4 \\ & {{\left( {{4}^{2}} \right)}^{x}}=4 \end{align}$ Apply the principle of exponential equality: $\text{if }{{a}^{m}}={{a}^{n}}\text{ then }m=n$. $\begin{align} & {{4}^{2x}}={{4}^{1}} \\ & 2x=1 \\ & x=\frac{1}{2} \end{align}$ Check: Substitute $x=\frac{1}{2}$in ${{16}^{x}}=4$. ${{16}^{\frac{1}{2}}}=4$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.