Answer
The equivalent expression for ${{\log }_{a}}48-{{\log }_{a}}12$ is ${{\log }_{a}}4$.
Work Step by Step
${{\log }_{a}}48-{{\log }_{a}}12$
Apply the quotient rule for logarithms,
$\begin{align}
& {{\log }_{a}}48-{{\log }_{a}}12={{\log }_{a}}\left( \frac{48}{12} \right) \\
& ={{\log }_{a}}4
\end{align}$
