Answer
2.
Work Step by Step
${{\log }_{9}}81$
$\begin{align}
& {{\log }_{9}}81={{\log }_{9}}{{9}^{2}} \\
& =2{{\log }_{9}}9
\end{align}$
Using log rules:
$\begin{align}
& {{\log }_{9}}81=2\left( 1 \right) \\
& =2
\end{align}$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 12 - Exponential Functions and Logarithmic Functions - Review Exercises: Chapter 12 - Page 843: 20
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