Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Review Exercises: Chapter 12 - Page 843: 42

Answer

2.54995.

Work Step by Step

${{\log }_{a}}\sqrt{7}={{\log }_{a}}{{7}^{\frac{1}{2}}}$ Apply the power rule for logarithms as follows. ${{\log }_{a}}\sqrt{7}=\frac{1}{2}{{\log }_{a}}7$ Substitute ${{\log }_{a}}7=5.0999$. $\begin{align} & {{\log }_{a}}\sqrt{7}=\frac{1}{2}\left( 5.0999 \right) \\ & =2.54995 \end{align}$
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