Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Review Exercises: Chapter 12 - Page 843: 41

Answer

3.2698.

Work Step by Step

${{\log }_{a}}3.5$ Simplify the logarithm ${{\log }_{a}}3.5$ as follows. ${{\log }_{a}}3.5={{\log }_{a}}\frac{7}{2}$ Apply the quotient rule for logarithms as follows. ${{\log }_{a}}3.5={{\log }_{a}}7-{{\log }_{a}}2$ Substitute ${{\log }_{a}}2=1.8301\text{ and }{{\log }_{a}}7=5.0999$. $\begin{align} & {{\log }_{a}}3.5=5.0999-1.8301 \\ & =3.2698 \end{align}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.