Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-12 - Cumulative Review - Page 846: 28

Answer

$y=-10x-8$

Work Step by Step

A linear equation $y=ax+b$ is uniquely defined by two points. To find the coefficients $a$ and $b$, substitute the points $(0,-8)$ and $(-1,2)$ in the equation. We get $$\begin{cases} -8&=a\cdot0+b\\ 2&=-a+b \end{cases}$$ We get from the first equation $b=-8$ and from the second $2=-a-8$ or $a=-10.$ Our linear equation is $y=-10x-8$
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